0.3n^2-2n=(n^2)

Solution for 0.3n^2-2n=(n^2) equation:

0.3n^2-2n=(n^2)

We move all terms to the left:

0.3n^2-2n-((n^2))=0

determiningTheFunctionDomain
0.3n^2-2n-n^2=0

We add all the numbers together, and all the variables

0.3n^2-n^2-2n=0

We add all the numbers together, and all the variables

-0.7n^2-2n=0

a = -0.7; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-0.7)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-0.7}=\frac{0}{-1.4}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-0.7}=\frac{4}{-1.4}
=-2+1/1.1666666666667
$